Hydraulic Cylinder Force and Speed Calculator

Cylinder push force = pressure × piston area (π ÷ 4 × bore²); speed = flow × 231 ÷ (60 × area) in inches per second.

Estimate only. Results are estimates. Verify against the applicable code and manufacturer specifications before relying on them for safety-related work.

in
in
psi
gpm
in
Push force (extend)
31,415.9lbf
Push force in US tons15.71 tons
Pull force (retract)23,561.9 lbf
Extend speed3.37 in/s
Retract speed4.49 in/s
More results (2)
Extend time
7.1 s
Retract time
5.3 s

Show the math

Piston area = π ÷ 4 × 4² = 12.57 in²; rod-side area = 9.42 in²
Push force = 2,500 psi × 12.57 in² = 31,415.9 lbf (15.71 tons)
Pull force = 2,500 × 9.42 = 23,561.9 lbf
Extend speed = 11 gpm × 231 ÷ (60 × 12.57) = 3.37 in/s; retract 4.49 in/s

Rounded the same way as the result above.

How it works

Hydraulic force is pressure acting on area. On extension, oil pushes on the full piston face. On retraction it pushes on the smaller annulus (piston minus rod), so pull force is lower than push force but speed is higher for the same flow.

Speed comes from flow divided by area: a gallon is 231 cubic inches, so speed in in/s = gpm × 231 ÷ (60 × area in²). Stroke divided by speed gives the cycle time.

A = π ÷ 4 × bore² Push = P × A Pull = P × (A − π ÷ 4 × rod²) Speed (in/s) = gpm × 231 ÷ (60 × A)

Worked example

A 4-inch bore, 2-inch rod cylinder at 2,500 psi fed by an 11 gpm pump, 24-inch stroke (typical log splitter):

  1. Piston area = π ÷ 4 × 4² = 12.57 in²; rod-side area = 9.42 in²
  2. Push force = 2,500 psi × 12.57 in² = 31,415.9 lbf (15.71 tons)
  3. Pull force = 2,500 × 9.42 = 23,561.9 lbf
  4. Extend speed = 11 gpm × 231 ÷ (60 × 12.57) = 3.37 in/s; retract 4.49 in/s
InputValue
Bore diameter4 in
Rod diameter2 in
Pressure2500 psi
Pump flow11 gpm
Stroke length24 in
ResultValue
Push force (extend)31,415.9 lbf
Push force in US tons15.71 tons
Pull force (retract)23,561.9 lbf
Extend speed3.37 in/s
Retract speed4.49 in/s
Extend time7.1 s
Retract time5.3 s

Assumptions and limits

  • Ideal calculation. Seal friction and back pressure reduce real force by roughly 5–10%.
  • Uses the pressure you enter at the cylinder, not the pump relief setting; hose and valve losses reduce it.
  • Retract time uses the annulus area; in-line flow controls or regeneration circuits change these speeds.

Common questions

How many tons of force does a log splitter cylinder make?

Push force in tons is pressure × piston area ÷ 2,000. A 4-inch bore at 2,500 psi is about 15.7 tons; a 5-inch bore is about 24.5 tons.

Why is retract faster than extend?

On retract the rod takes up part of the piston area, so the same flow fills less volume per inch and the rod moves faster, but with less force.

What flow do I need for a target speed?

Rearrange the speed formula: gpm = speed (in/s) × 60 × area ÷ 231.

Sources

  • Fluid power basics: force = pressure × area; flow = area × velocity; 231 cubic inches per US gallon.

Updated 2026-09-30