Voltage Drop Calculator

Voltage drop = 2 × K × current × one-way length ÷ circular mils for single-phase (K = 12.9 for copper, 21.2 for aluminum).

Estimate only. Results are estimates. Verify against the applicable code and manufacturer specifications before relying on them for safety-related work.

V
A
ft
Conductor material
Phase
Voltage drop
5.9V
Percent drop2.46 %
Voltage at the load234.1 V

Show the math

VD = 2 × K × I × L ÷ CM = 2 × 12.9 × 40 × 150 ÷ 26,240 = 5.9 V
Percent drop = 5.9 ÷ 240 × 100 = 2.46%
Voltage at load = 240 − 5.9 = 234.1 V

Rounded the same way as the result above.

How it works

Every wire has resistance, so current flowing through it loses voltage before reaching the load. Too much drop makes motors run hot, lights dim, and electronics misbehave.

This uses the standard circular-mil formula with a constant K for the conductor's resistivity (12.9 ohm-cmil/ft for copper and 21.2 for aluminum at about 75 °C). Length is one-way distance from source to load; the formula doubles it for single-phase because current flows out and back.

Single-phase: VD = 2 × K × I × L ÷ CM Three-phase: VD = 1.732 × K × I × L ÷ CM K = 12.9 (Cu), 21.2 (Al); L = one-way length (ft); CM = circular mils

Worked example

A 240 V single-phase load drawing 40 A, 150 feet away, on 6 AWG copper:

  1. VD = 2 × K × I × L ÷ CM = 2 × 12.9 × 40 × 150 ÷ 26,240 = 5.9 V
  2. Percent drop = 5.9 ÷ 240 × 100 = 2.46%
  3. Voltage at load = 240 − 5.9 = 234.1 V
InputValue
Source voltage240 V
Load current40 A
One-way length150 ft
Wire size6 AWG
Conductor materialCopper
PhaseSingle-phase
ResultValue
Voltage drop5.9 V
Percent drop2.46 %
Voltage at the load234.1 V

Wire sizes and circular mils

Wire sizeCircular mils
14 AWG4110
12 AWG6530
10 AWG10380
8 AWG16510
6 AWG26240
4 AWG41740
3 AWG52620
2 AWG66360
1 AWG83690
1/0 AWG105600
2/0 AWG133100
3/0 AWG167800
4/0 AWG211600
250 kcmil250000
350 kcmil350000
500 kcmil500000
Show the wire sizes and circular mils table
Wire sizeCircular mils
14 AWG4110
12 AWG6530
10 AWG10380
8 AWG16510
6 AWG26240
4 AWG41740
3 AWG52620
2 AWG66360
1 AWG83690
1/0 AWG105600
2/0 AWG133100
3/0 AWG167800
4/0 AWG211600
250 kcmil250000
350 kcmil350000
500 kcmil500000

Circular-mil areas from NEC Chapter 9, Table 8.

Assumptions and limits

  • Resistive DC-style approximation. It ignores reactance and power factor, which matters on large conductors, long runs, and inductive loads.
  • Resistance is taken at about 75 °C. Cooler conductors drop slightly less.
  • The NEC recommends (not requires) at most 3% drop on a branch circuit and 5% total for feeder plus branch.

Common questions

How much voltage drop is acceptable?

The NEC informational notes recommend a maximum of 3% on a branch circuit and 5% combined for feeder and branch. Some equipment specifies stricter limits.

How do I reduce voltage drop?

Use a larger wire, shorten the run, raise the system voltage (240 V instead of 120 V), or use copper instead of aluminum.

Do I use one-way or round-trip length?

Enter one-way length. The formula already accounts for the return path.

Sources

  • Circular-mil voltage drop formula with K = 12.9 (copper) and 21.2 (aluminum) ohm-cmil/ft at about 75 °C, consistent with the conductor resistances in NEC Chapter 9, Table 8.
  • Circular mil areas: NEC Chapter 9, Table 8.
  • 3% branch-circuit and 5% total recommendations: NEC informational notes to 210.19(A) and 215.2(A)(2). These are recommendations, not requirements.

Updated 2026-09-30